160+10x=10x^2

Solution for 160+10x=10x^2 equation:

160+10x=10x^2

We move all terms to the left:

160+10x-(10x^2)=0

determiningTheFunctionDomain
-10x^2+10x+160=0

a = -10; b = 10; c = +160;
Δ = b2-4ac
Δ = 102-4·(-10)·160
Δ = 6500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6500}=\sqrt{100*65}=\sqrt{100}*\sqrt{65}=10\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{65}}{2*-10}=\frac{-10-10\sqrt{65}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{65}}{2*-10}=\frac{-10+10\sqrt{65}}{-20}
$